Answer : B
the distance between the points (4,3) and (2,-1)
We apply distance formula
[tex]d^2= (x_2-x1)^2 + (y_2-y_1)^2[/tex]
(x1,y1) is (4,3)
(x2,y2) is (2,1)
[tex]d^2= (2-4)^2 + (-1-3)^2[/tex]
[tex]d^2= (-2)^2 + (-4)^2[/tex]
d^2 = 4+16 = 20
Take square root on both sides
So [tex]d=2\sqrt{5}[/tex]
the distance between the points (4,3) and (2,-1) is 2sqrt(5)
