[tex]3\frac{1}{6}[/tex] gallons are left in the tank.
To determine the total amount left in the tank = Total capacity of the tank – Total amount of water poured out in gallons
= 9.5 (also expressed as 95/10) – [tex]6\frac{1}{3}[/tex] (otherwise expressed as [tex]\frac{19}{3}[/tex] )
Before solving further, we look for the lowest common denominator (LCD) of both denominators (10 and 3) since we are dealing with fractions.
Hence,
LCD of 10 and 3 = 30
Therefore,
= [tex]\frac{95}{10}[/tex] – [tex]\frac{19}{3}[/tex]
= (95 x 3) – (19 x 10) / 30
= (285) – (190) / 30
= 285 – 190 / 30
= [tex]\frac{95}{30}[/tex]
= [tex]\frac{19}{6}[/tex]
= [tex]3\frac{1}{6}[/tex] gallons
Thus, the total amount of gallons of water left in the tank is [tex]3\frac{1}{6}[/tex] gallons.
The above expression is a typical number problem which has an element of fraction in it. Fraction consists of numerator and denominators which are usually jointly factored out to derive a solution to a given math problem.
It is essential to apply BODMAS while solving a fraction problem like the one given. And notably, the arms of BODMAS that were applied are Division, Multiplication and Addition.
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