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Yanick and Nancy drive two identical 1380 kilogram cars at 30 m/sec. Yanick slams on the brakes and his car comes to a stop in 1.02 seconds. Nancy lightly applies the brakes and stops her car in 3.7 seconds. Calculate the stopping force for each car.

Respuesta :

Yanick drive the car at initial speed of 30 m/s and slams the brakes and stop the car in 1.02 s

So here the acceleration of the car is given as

[tex]a = \frac{v_f - v_i}{t}[/tex]

[tex]a = \frac{30 - 0}{1.02}[/tex]

[tex]a = 29.41 m/s^2[/tex]

now the force to stop the car is given as

[tex]F = ma[/tex]

[tex]F = 1380\times 29.41 = 40588.2 N[/tex]

Nancy drive the car at initial speed of 30 m/s and slams the brakes and stop the car in 3.7 s

So here the acceleration of the car is given as

[tex]a = \frac{v_f - v_i}{t}[/tex]

[tex]a = \frac{30 - 0}{3.7}[/tex]

[tex]a = 8.11 m/s^2[/tex]

now the force to stop the car is given as

[tex]F = ma[/tex]

[tex]F = 1380\times 8.11 = 11189.2 N[/tex]

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