NVM it is D
Find the surface area of the cylinder with a radius of 9 inches and a height of 11 inches in terms of pi
a) 198 pi in^2
b) 234 pi in^2
c) 846 pi in^2
d) 360 pi in^2

Respuesta :

T.S.A of a cylinder = 2[tex] \pi [/tex]r² + 2[tex] \pi [/tex]rh
                              =2(9)²[tex] \pi [/tex] + 2(9)(11)[tex] \pi [/tex]
                              = 162[tex] \pi [/tex] + 198[tex] \pi [/tex]
                             = 160[tex] \pi [/tex] in²

And yes the Answer is D. 360[tex] \pi [/tex] in²