Answer : The partial pressure of [tex]H_2[/tex] is 98.825 kPa.
Solution : Given,
Total pressure of hydrogen water vapor = 1 atm = 101.325 kPa (1 atm = 101.325 kPa)
Partial pressure of water vapor = 2.5 kPa
Dalton's law of partial pressure : It is defined as the total pressure exerted is equal to the sum of the partial pressure of individual gases.
Formula used :
[tex]P_{Total}=\sum_{i=1}^nP_i[/tex]
[tex]P_{Total}[/tex] = Total pressure
[tex]P_{i}[/tex] = Partial pressure of individual gases
[tex]P_{Total}=P_{H_2}+P_{\text{ Water vapor}}[/tex]
Now put all the given values in this expression, we get
[tex]101.325kPa=P_{H_2}+2.5kPa[/tex]
[tex]P_{H_2}=98.825kPa[/tex]
Therefore, the partial pressure of [tex]H_2[/tex] is 98.825 kPa.