[tex]\dfrac{7}{6}-(5x-3)=\dfrac{1}{5}x-12\\\\\dfrac{7}{6}-5x+3=\dfrac{1}{5}x-12\qquad|\text{multiply both sides by LCM(6, 5)=30}\\\\30\cdot\dfrac{7}{6}-30\cdot5x+30\cdot3=30\cdot\dfrac{1}{5}x-30\cdot12\\\\5\cdot7-150x+90=6\cdot1x-360\\\\35-150x+90=6x-360\\\\-150x+(35+90)=6x-360\qquad|\text{subtract 6x from both sides}\\\\-156x+125=-360\qquad|\text{subtract 125 from both sides}\\\\-156x=-485\qquad|\text{divide both sides by (-156)}\\\\x=\dfrac{485}{156}[/tex]
