Starting from 300 feet away, a car drives toward you. It then passes by you at a speed of 48 feet per second. The distance d (in feet) of the car from you after t seconds is given by the equation d=|300−48t|. At what times is the car 60 feet from you?

In this question, you are given the initial distance (300ft), car velocity(48ft/s) and the final distance(60ft). You are also given the equation to calculating the distance, so this question should be easier. The question is when the time where the distance is 60 ft. So the answer would be:

distance= 300-48t

60 = 300ft- 48t

48t= 300- 60=240

t= 5

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Starting from 300 feet away, a car drives toward you. It then passes by you at a speed of 48 feet per second. The distance d (in feet) of the car from you after t seconds is given by the equation ​d=|300−48t|. At what times is the car 60 feet from you?

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Starting from 300 feet away, a car drives toward you. It then passes by you at a speed of 48 feet per second. The distance d (in feet) of the car from you after t seconds is given by the equation d=|300−48t|. At what times is the car 60 feet from you?