Respuesta :
Answer : The mass of solute in solution is [tex]1.09\times 10^2g[/tex].
Solution : Given,
Molarity = 0.730 M
Volume of solution = 1.421 L
Molar mass of sodium carbonate = 105.98 g/mole
Formula used for Molarity :
[tex]Molarity=\frac{w}{M\times V}[/tex]
where,
w = mass of solute
M = Molar mass of solute
V = volume of solution in liter
Sodium carbonate is solute and water is solvent.
Now put the given values in above formula, we get the mass of solute in solution.
[tex]0.730mole/L=\frac{w}{(105.98g/mole)\times (1.412L)}[/tex]
By rearranging the terms, we get
[tex]m=109.247g=1.09\times 10^2g[/tex]
Therefore, the mass of solute in solution is [tex]1.09\times 10^2g[/tex].
The mass of the NaCO₃ solute in the solution is 109.93 grams.
What is molarity?
Molarity is define as the number of moles of solute present in per liter of solution i.e.
M = n/V
From these equation first we calculate the moles of sodium carbonate in 1.421L of solution, whose molarity is 0.730 as:
Moles of NaCO₃ = 0.730 × 1.421 = 1.037 moles
Now we calculate mass of NaCO₃ by using the 1.037 moles as follow:
n = W/M, where
M = molar mass of NaCO₃ = 105.98 g/mole
W = required mass ?
W = 1.037mol × 105.98g/mol = 109.93 grams
Hence, 109.93 grams is the mass of solute.
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