Respuesta :

devin258

[tex] \frac{x {}^{3} - 3x {}^{2} - 10x {}^{2} + 30x + 4x - 12 }{x - 3 } \\ \frac{x {}^{2} \times (x - 3) - 10x \times (x - 3) + 4 \times (x - 3) }{x - 3} \\ \frac{(x - 3)(x {}^{2} - 10x + 4 )}{x - 3} \\ x {}^{2} - 10x + 4[/tex]