Answer : D
[tex]\frac{2}{3z} - (\frac{5}{6z^2} - \frac{z+3}{z})[/tex]
[tex]\frac{2}{3z} - \frac{5}{6z^2} + \frac{z+3}{z}[/tex]
We take common denominator
Least common denominator is 6z^2
We try to get 6x^2 in all the denominators
[tex]\frac{2*2z}{3z*2z} - \frac{5}{6z^2} + \frac{(z+3)*6z}{z*6z}[/tex]
[tex]\frac{4z}{6z^2} - \frac{5}{6z^2} + \frac{6z^2+18z}{6z^2}[/tex]
[tex] \frac{4z-5 +6z^2+18z}{6z^2}[/tex]
[tex] \frac{6z^2+22z-5}{6z^2}[/tex]
