Respuesta :

1st:x

2nd x+2

3rd: x+4

(x)+(x+2) = 3(x+4)-31

distribute

2x+2 = 3x+12-31

2x+2 =3x-19

subtract 2x from each side

2 = x-19

add 19 to each side

21 =x

Answer: 21,23,25

Using a system of equations, it is found that the integers are 21, 23 and 25.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the three consecutive odd integers are:

n, n + 2 and n + 4.

The sum of the first and second is 31 less than 3 times the third, hence:

[tex]n + n + 2 = 3(n + 4) - 31[/tex]

[tex]3n + 12 - 31 = 2n + 2[/tex]

[tex]n = 21[/tex]

n = 21

n + 2 = 23

n + 4 = 25

Hence the integers are 21, 23 and 25.

More can be learned about a system of equations at https://brainly.com/question/24342899