cche2344
contestada

given the equation 2ax-10=(a-2)x+5a, where a is not equal to -2. When this equation is solved for x, the value of x equals what?

Respuesta :

wegnerkolmp2741o

2ax-10=(a-2)x+5a

distribute

2ax-10=ax-2x+5a

subtract 2ax from each side

-10 = ax-2x-2ax +5a

subtract 5a to each side

-10 -5a = ax -2x-2ax

combine like terms

-10-5a = -2x-ax

factor out an x

-10 -5a = x(-2-a)

factor out -5 on the left and -1 on the right

-5(2+a)= -x(2+a)

divide by -(2+a)

5 = x

Answer x=5

Answer: The value of x is equal to 5.

Step-by-step explanation:

Since we have given that

[tex]2ax=(a-2)x+5a[/tex]

We need to solve for the value of 'x'.

First we simplify it :

[tex]2ax-10=ax-2x+5a\\\\2ax-ax-10=-2x+5a\\\\ax-10=-2x+5a\\\\ax+2x=5a+10\\\\x(a+2)=5(a+2)\\\\x=5[/tex]

Hence, the value of x is equal to 5.