Answer:
-x^2 - 20x -4 = 0
Step-by-step explanation:
I assume you meant (x-8)(2x+3) = (3x-5)(x+4).
Perform the two indicated multiplications and then combine like terms:
2x^2 + 3x - 16x - 24 = 3x^2 + 12x - 5x - 20
Combine the x terms on each side:
2x^2 - 13x - 24 = 3x^2 + 7x - 20
Subtract 3x^2 from both sides:
-x^2 - 13x - 24 = 7x - 20
Subtract 7x from both sides:
-x^2 - 20x - 24 = -20
Add 20 to both sides:
-x^2 - 20x -4 = 0 This is the desired quadratic equation.
