caseygrace57 caseygrace57

26-10-2018
Mathematics

contestada

find the standard form of the following equation y=(x-3)^2-5

Respuesta :

altavistard altavistard

26-10-2018

Answer:

y = x^2 - 6x + 4

Step-by-step explanation:

The equation of a parabola in "standard form" is y = ax^ 2 + bx + c.

Expanding y = (x-3)^2 -5, we get y = x^2 - 6x + 9 - 5, or y = 1x^2 - 6x + 4. y = x^2 - 6x + 4 would be an adequate answer also.

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