Answer:
Step-by-step explanation:
Given is a function in x as
[tex]f(x)=2x^3-x^2-8x+4[/tex]
We have to find the zeroes of the function
Since this is a cubic function this function has three zeroes.
Let us try to factorise this function by grouping two terms together.
[tex]x^2(2x-1)-4(2x-1)\\= (2x-1)(x^2-4)[/tex]
=[tex](2x-1)(x-2)(x+2)[/tex]
Equate each factor to 0 to find zeroes as
[tex]-2,2,\frac{1}{2}[/tex]
