1. The sum of 122 and 98 is (122+98)
Two-thirds of the sum of 122 and 98 is
[tex]\dfrac{2}{3}\cdot (122+98).[/tex]
2. 99 divided by 10 is [tex]\dfrac{99}{10}.[/tex] The sum of 84 and 3 is (84+3).
99 divided by 10, then multiplied by the sum of 84 and 3 is
[tex]\dfrac{99}{10}\cdot (84+3).[/tex]
3. (10+5)=15,
1=+53=63.
Since 15<63, then (10+5)<10+53.
4. (16-4)+9=12+9=21,
(16-4)=12.
Since 21>12, then (16-4)+9>(16-4).
