How many joules are required for heating 65g of water from 12 degree Celsius to 76 degree Celsius

Question

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Respuesta :

znk znk · Answer 1 · 2018-09-30T21:25:15+02:00

The amount of energy required is 17 kJ.

The formula for the heat (q) is

q = mCΔT

m = 65 g; C = 4.184 J·°C⁻¹g⁻¹; ΔT = T_f – T_i = 76 °C – 12 °C = 64 °C

q = 65 g × 4.184 J·°C⁻¹g⁻¹ × 64 °C = 17 000 J = 17 kJ

Answer Link

saadhussain514 saadhussain514 · Answer 2 · 2018-10-01T04:40:05+02:00

The answer will be 17000 joules

With knowledge of the specific heat capacity of a substance, its mass and the temperature change, we can get heat at this temperature change using:

[tex]ΔH= m * C * ΔT[/tex]

[tex]Δ[/tex] = Δ

where

ΔH = Change in enthalpy (J)

m = Mass of substance, being heated (g) i.e. water in this question

C = Specific heat capacity (J/g° C)

ΔT= change in temperature (°C)

We know

The mass of water = 65g

ΔT = 76°C − 12°C = 64°C

The specific heat capacity of water is 4.18J/g °C

So,

[tex]ΔH = 65g * 4.18Jg^{o}C * 64^{o}C[/tex]

ΔH = 17388.8J

ΔH = 17000J (2 significant figures)

17000J will required to heat water