/3x+2/>7
how would I sovle this im vary stuck

x < - 3 or x > [tex]\frac{5}{3}[/tex]
The first thing to do is clear the bars and split the inequality into 2 parts
3x + 2 < - 7 or 3x + 2 > 7 → ( this is the pattern for greater than)
3x + 2 < - 7
subtract 2 from both sides
3x < - 9 ⇒ x < - 3
or 3x + 2 > 7
subtract 2 from both sides
3x > 5 ⇒ x > [tex]\frac{5}{3}[/tex]