The two points on the coordinate plane represent Jane's house and her friend's house. Find the distance between the houses.
    
  A. √ 8  units
  B. 2√ 10  units
  C. √ 10  units
  D. 2√ 17  units

The two points on the coordinate plane represent Janes house and her friends house Find the distance between the houses A 8 units B 2 10 units C 10 units D 2 1 class=

Respuesta :

Answer:

The answer is 2[tex]\sqrt{17}[/tex], we need to use the distance between point formula; I recommend you search in the internet another examples.

Step-by-step explanation:

We need to calculate the distance between points, so we need to use the formula d=[tex]\sqrt{(x_{1}- x_{2} )^{2}+(y_{1}-y_{2})  ^{2}}[/tex]

You can use Janes house (-5,-2) or friends house like (3,-4) point 1 or 2, it is the same way.

when we substitute in the formula

:

d = [tex]\sqrt{(-5-2)^{2}+(-2-(-4))^{2}  }[/tex]

d=[tex]\sqrt{(-8)^{2}+(2)^{2} }[/tex]

d=[tex]\sqrt{64+4}[/tex] = [tex]\sqrt{68}[/tex]

We need to reduce this result, so we need to find two number wich on of those can we solve the square root, if we divide 68/4 we find:

d=[tex]\sqrt{4*17}[/tex]

And 4 has exact square root result, so the result in:

2[tex]\sqrt{17}[/tex]

Answer:

||10| – |5||

= |10 – 5|

= |5|

= 5

||–10| + |6||

= |10 + 6|

= |16|

= 16

If both the points lie on a horizontal or a vertical line, absolute values are used, otherwise the distance formula is used to find the distance between the points.

(9, 5), (1, 5)

||9| – |1||

= |9 – 1|

= |8|

= 8 units

(0, 0), (4, 3)

(4−0)2+(3−0)2−−−−−−−−−−−−−−−√

=42+32−−−−−−√

=16+9−−−−−√

=25−−√

= 5 units

(–1, –3), (–1, 8)

||–3| + |8||

= |3 + 8|

= |11|

= 11 units

Step-by-step explanation: penn!