contestada

If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a point on the graph?

Since the function is even, the outputs of a negative x-value and a positive x-value are the same.

Since the function is even, the outputs of a negative y-value and a positive y-value are the same.

The graph has rotational symmetry, so the point will be reflected across the y-axis.

The graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.

PLEASE HELP IM IN THE MIDDLE OF A TEST

Respuesta :

kudzordzifrancis

If [tex]f(x)[/tex] is an even function, then [tex]f(x)=f(-x)[/tex]. In this case, [tex]f(6)=8=f(-6)[/tex].


This is because an even function is symmetric about the [tex]y-axis[/tex]. Hence the outputs of a negative x-value and a positive x-value are the same.


The correct option is the first option.

Since the graph is even, the outputs of a negative x-value and a positive x-value are the same.


maxisacow

Answer:

A

Step-by-step explanation:

just took test on edge