contestada

Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-10, 12) and point (5, 3) rounded to the nearest tenth?


17.5 units


10.29 units


175 units


13 units

Respuesta :

kudzordzifrancis
The distance between the two points is;

[tex]d = \sqrt{( {(5--10)}^{2 } + (3 - 12) {}^{2} )} [/tex]
[tex]d = \sqrt{((5 + 10) {}^{2} + (3 - 12) {}^{2} } [/tex]
[tex]d = \sqrt{(( {15}^{2} + ( { - 9}^{} ) {}^{2} )} [/tex]
[tex]d = \sqrt{(225 +81)} [/tex]
[tex]d = \sqrt{306} [/tex]
[tex]d = 3 \sqrt{34} [/tex]
[tex]d = 17.4929[/tex]
To the nearest tenth,

[tex]d = 17.5 \: units[/tex]
Rounding to the nearest tenth is the same as rounding to one decimal place

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