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if a person weighs 717 N on earth and 5320 N on the surface due to gravity on that planet? of a nearby planet, what is the acceleration

a. 83.6

b. 72.7

c. 63.2

d. 53.1

Respuesta :

jasondunstan18

The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.

Answer:

[tex]g'=72.7\ m/s^2[/tex]

Explanation:

It is given that,

Weight of the person on Earth, W = 717 N

Weight of a person is given by the following formula as :

[tex]W=mg[/tex]

g is the acceleration due to gravity on earth

[tex]m=\dfrac{W}{g}[/tex]

[tex]m=\dfrac{717\ N}{9.81\ m/s^2}[/tex]

m = 73.08 kg

The mass of an object is the amount of matter contained in it. It is same everywhere.

Let W' is the weight of the person on the surface of a nearby planet, W' = 5320 N

g' is the acceleration due to gravity on that planet. So,

[tex]g'=\dfrac{W'}{m}[/tex]

[tex]g'=\dfrac{5320\ N}{73.08\ kg}[/tex]                

[tex]g'=72.79\ m/s^2[/tex]

or

[tex]g'=72.7\ m/s^2[/tex]

So, the acceleration due to gravity on that planet is [tex]72.79\ m/s^2[/tex]. So, the correct option is (b). Hence, this is the required solution.     

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