f(x) = x^3 + 5x^2 - 4x - 20
The zeros of the polynomial function: x^3 + 5x^2 - 4x - 20 = 0
x^3 + 5x^2 - 4x - 20 = 0
x^2(x + 5) - 4(x + 5) = 0
(x^2 - 4)(x + 5) = 0
(x + 2)(x - 2)(x + 5) = 0
(x + 2) = 0; x = -2
(x - 2) = 0; x = 2
(x + 5) = 0; x = -5
Answer is the first one
x = -5, x = -2, x = 2
