Respuesta :
Since the graph is a straight line, its equation is of the form;
[tex]y = mx + c[/tex]
Where m is the slope and c is the y intercept
We can use any two points on the straight line to find the value of m and c.
Let us use (0,30) and (4,150)
[tex]m = \frac{150 - 30}{4 - 0} [/tex]
This simplifies to,
[tex]m = \frac{120}{4} = 30[/tex]
Let us substitute the value of m to obtain,
[tex]y = 30x + c[/tex]
Substitute any of the points to find c. It is easier to use (0,30).
[tex]30 = 30(0) + c[/tex]
[tex]c = 30[/tex]
The equation of the graph now becomes,
[tex]y = 30x + 30[/tex]
So in 10 weeks Ben will collect,
[tex]y = 30(10) + 30[/tex]
[tex]y = 300 + 30[/tex]
[tex]y = 330[/tex]
Ben will collect 330 papers.
You can also use any two points to find the equation of this line.
[tex]y = mx + c[/tex]
Where m is the slope and c is the y intercept
We can use any two points on the straight line to find the value of m and c.
Let us use (0,30) and (4,150)
[tex]m = \frac{150 - 30}{4 - 0} [/tex]
This simplifies to,
[tex]m = \frac{120}{4} = 30[/tex]
Let us substitute the value of m to obtain,
[tex]y = 30x + c[/tex]
Substitute any of the points to find c. It is easier to use (0,30).
[tex]30 = 30(0) + c[/tex]
[tex]c = 30[/tex]
The equation of the graph now becomes,
[tex]y = 30x + 30[/tex]
So in 10 weeks Ben will collect,
[tex]y = 30(10) + 30[/tex]
[tex]y = 300 + 30[/tex]
[tex]y = 330[/tex]
Ben will collect 330 papers.
You can also use any two points to find the equation of this line.