Respuesta :

kenmyna

The number of O atoms in 7.3 x10 ^-3 g of CaSO4 x 2H2O  are

= 1.535 x10^20  atoms


calculation

step 1: calculate the moles of CaSO4 . 2H2O

  • moles = mass/molar mass
  • molar mass is of CaSO4.H2O=Mw of Ca + S +O +H2O
  • = 40+32 +( 4x16)  +2( (1x2)+16)=  172 g/mol

  • moles is therefore= 7.3 x10^-3 g/172 g/mol=   4.244  x10^-5 moles

find the moles of O

  • since there are 6 atoms of O the moles of O=   6 x ( 4.244 x10^-5)= 0.000255 moles

by use  of Avogadro's law constant find the number of O atom

  • that is  1 mole     =       6.02 x10 ^23 atoms

                      0.000255 moles=? atoms

  • by cross multiplication

 = 0.000255 moles  x(6.02 x10^23 atoms)/ 1 mole=  1.535  x10^20 atoms