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Answer: y = 4x-3
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To get this answer, first note that the slope of the given line y = -1/4x+2 is m = -1/4. We take the slope -1/4 and flip the fraction, and then flip the sign. So we end up with 4/1 or just 4. The perpendicular slope is 4, which is part of the answer we want.
We have y = mx+b turn into y = 4x+b. Plug in (x,y) = (-2,-11) and then solve for b
y = 4x+b
-11 = 4*(-2)+b .... replace x with -2, replace y with -11
-11 = -8+b
-11+8 = -8+b+8 .... add 8 to both sides
-3 = b
b = -3
So y = 4x+b turns into y = 4x-3 which is the answer
The linear equation in slope-intercept form of the line that is perpendicular to y= -1/4x+2 and passes through (-2, -11) is: y = 4x - 3
Recall:
- Linear equation can be written as y = mx + b (slope-intercept form), where m = slope, b = y-intercept.
- Slope of perpendicular lines are negative reciprocal of each other. i.e. if the slope of a line is n/m, the slope of the line perpendicular to it will be -m/n.
Given a line passes through (-2, -11) and is perpendicular to y = -1/4x + 2:
the slope (m) of the line will be the negative reciprocal to the slope of y = -1/4x + 2.
- Slope of y = -1/4x + 2 is -1/4.
- Negative reciprocal of -1/4 is: 4
- The slope (m) of the perpendicular line is therefore 4.
Write the equation in point-slope form using the point and the slope value of the perpendicular line, then rewrite in slope-intercept form.
Substitute (a, b) = (-2, -11) and m = 4 into y - b = m(x - a))
- Thus:
y - (-11) = 4(x - (-2))
y + 11 = 4(x + 2)
y + 11 = 4x + 8
y + 11 - 11 = 4x + 8 - 11
y = 4x - 3
Therefore, the equation in slope-intercept form of the line that is perpendicular to y= -1/4x+2 and passes through (-2, -11) is: y = 4x - 3
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