given that acceleration due to gravity is a = -10 m/s^2
initial speed will be ZERO
and we need to find the displacement in t = 8 s
now we can use kinematics equation to find the displacement
[tex]\delta y = v_y * t + \frac{1}{2}at^2[/tex]
now plug in all values in it
[tex]\delta y = 0* 8 + \frac{1}{2}*(-10)*8^2[/tex]
[tex]\delta y = -320 m[/tex]
so it will displace downwards by 320 m