Answer:
Acceleration of the rider = 0.799 [tex]m/s^2[/tex]
Explanation:
We have equation of motion, [tex]v^2=u^2+2as[/tex], where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.
Initial speed of bicycle rider = 0 m/s
Final speed of bicycle rider = 8.24 m/s
Traveling distance = 42.5 meters.
Substituting
[tex]8.24^2=0^2+2*a*42.5\\\\a=0.799m/s^2[/tex]
Acceleration of the rider = 0.799 [tex]m/s^2[/tex]
