Answer: 25%
Step-by-step explanation:
Given : Roger has a nail that is 12 centimeters long.
He measures and records the length of the nail as 15 centimeters.
i.e. Estimated length = 15 cm and Actual length = 12 cm
The percent error in Rogers measurements is given by :-
[tex]\dfrac{|\text{Estimated-Actual}|}{\text{Actual}}\times100\\\\=\dfrac{|12-15|}{12}\times100\\\\=\dfrac{3}{12}\times100=25\%[/tex]
Hence, the percent error in Rogers measurements is 25%.
