Respuesta :
The molecular mass of calcite is 100.085 (given).
Atomic mass of calcium = 40.078 amu
Percent amount of calcium in calcite = [tex]\frac{40.078}{100.085}\times 100 = 40.044[/tex]%
The total mass of five mineral samples = [tex]10.9\pm 0.1 g[/tex] (given)
So, the mass of one sample = [tex]\frac{10.9}{5} = 2.18 g[/tex]
and [tex]\frac{0.1}{5} = 0.02 g[/tex]
The average mass of calcium in sample = [tex]\frac{2.18 g\times 40.044}{100} = 0.873 g[/tex]
and [tex]\frac{0.02 g\times 40.044}{100} = 0.008 g[/tex]
Hence, the average mass of calcium in each sample is [tex]0.873 g\pm 0.008 g[/tex].
