Respuesta :
A chemical reaction that lists only those species participating in the reaction are said to be an net ionic equation.
The general reaction between aqeous solutions of [tex]H_2SO_4[/tex] and [tex]KOH[/tex] is:
[tex]H_2SO_4(aq) + KOH(aq)\rightarrow K_2SO_4(aq)+H_2O(l)[/tex]
The balanced equation is:
[tex]H_2SO_4(aq) + 2KOH(aq)\rightarrow K_2SO_4(aq)+2H_2O(l)[/tex]
The ionic equation is:
[tex]2H^{+}(aq)+SO_{4}^{2-}(aq)+2K^{+}(aq)+2OH^{-}(aq)\rightarrow 2K^{+}(aq)+SO_{4}^{2-}(aq)+2H_2O(l)[/tex]
On cancelling the common ions from both the sides we get:
[tex]2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)[/tex]
Dividing the above reaction by 2:
[tex]H^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)[/tex]
Hence the net ionic equation that occurs between aqueous solutions of [tex]H_2SO_4[/tex] and [tex]KOH[/tex] is:
[tex]H^{+}(aq)+OH^{-}(aq)\rightarrow H_2O(l)[/tex]
The net ionic equation is defined as the reaction in which spectator ions ae eliminated and only participating ions are calculated. In the given equation,
[tex]\text{H}_2\text{SO}_4_{(aq)}+\text{KOH}_{(aq)}\rightarrow\text{K}_2\text{SO}_4_{(aq)}+\text{H}_2\text {O}_{(l)}[/tex], net ionic reaction has to be mentioned.
The balanced equation of sulphuric acid and potassium hydroxide is:
- [tex]\text{H}_2\text{SO}_4_{(aq)}+2 \;\text {KOH}_{(aq)}\rightarrow \text{K}_2\text{SO}_4_{(aq)}+2\;\text{H}_2{O}_{(l)}[/tex]
The ionic equation will be:
- [tex]2 \text H^+ + \text{SO}_4^{2-} +2 K^+ + 2 \text{OH}^- \rightarrow 2 \textK^+ + \text{SO}_4^{2-} + 2 \text {H}_2 \text{O}[/tex]
Cancelling the common ions, the equation becomes:
- [tex]\text H^+ + 2 \text{OH}^- \rightarrow 2 \text {H}_2 \text{O}[/tex]
Therefore, the net ionic equation that takes place in aqueous solution of sulfuric acid and potassium hydroxide is [tex]\text H^+ + 2 \text{OH}^- \rightarrow 2 \text {H}_2 \text{O}[/tex].
To know more about ionic equation, refer tot he following link:
https://brainly.com/question/2256173?referrer=searchResults
