Respuesta :
120 ag. The mass of 1.0 × 10^6 molecules of dimethylnitrosamine is 120 ag.
Step 1. Convert molecules to moles
Moles of DMN = 1.0 × 10^6 molecules DMN× (1 mol DMN)/(6.022 × 10^23 molecules DMN) = 1.66 × 10^(-18) mol DMN
Step 2. Convert moles to grams
The formula for dimethylnitrosamine (DMN) is (CH3)2N-N=O or C2H6N2O. The molar mass is 74.08 g/mol.
Mass of DMT = 1.66 × 10^(-18) mol DMN × (74.08 g DMN/1 mol DMN)
= 1.2 × 10^(-16) g DMT = 120 × 10^(-18) g = 120 ag
The mass of dimethylnitrosamine has been 0.000123 picogram.
The mass of the compound has been given as the moles of the compound with respect to the molar mass.
According to the Avogadro law, the mole of the compound has been the equivalent to the Avogadro number.
Mass of Dimethylnitrosamine:
The Avogadro number has been a constant with the value of [tex]6.023\;\times\;10^2^3[/tex]. The moles of dimethylnitrosamine in [tex]1.0\;\times\;10^6[/tex] molecules has been given as:
[tex]\rm 6.023\;\times\;10^2^3\;molecules=1\;mole\\1.0\;\times\;10^6=\dfrac{1}{6.023\;\times\;10^2^3}\;\times\;1.0\;\times\;10^6\;mole\\ 1.0\;\times\;10^6=0.166\;\times\;10^-^1^7\;mole[/tex]
The moles of dimethylnitrosamine has been [tex]0.166\;\times\;10^-^1^7[/tex].
The mass of dimethylnitrosamine has been given as:
[tex]\rm Mass=Moles\;\times\;Molar\;mass\\Mass=0.166\;\times\;10^-^1^7\;\times\;74.08\\Mass=12.3\;\times\;10^-^1^7\;\;g\\Mass=0.000123\;pg[/tex]
The mass of dimethylnitrosamine has been 0.000123 picogram.
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