Respuesta :

Answer:

             8.62 g of Hydrogen

Solution:

Molar mass of CH₄O (Methanol) is 32 g.mol⁻¹.

It means,

                  32 g of CH₄O contains  =  4 g of Hydrogen

Then,

             69 g of CH₄O will contain  =  X g of Hydrogen

Solving for X,

                    X  =  (69 g × 4 g) ÷ 32 g

                    X  =  8.62 g of Hydrogen