Respuesta :
Answer : 0.072 moles of water ([tex]H_{2}O[/tex]) produced by the reaction of 0.060mol of oxygen.
Explanation : Moles of oxygen([tex]O_{2}[/tex]) given = 0.060 mole
Moles of water ([tex]H_{2}O[/tex]) we need to calculate.
Step 1 : Write the balanced chemical equation.
[tex]4NH_{3} + 5O_{2}\rightarrow 4NO + 6 H_{2}O[/tex]
According to balanced equation 5 mole of [tex]O_{2}[/tex] reacts with 4 mole of [tex]NH_{3}[/tex] to give 4 moles of NO and 6 moles of [tex]H_{2}O[/tex].
Step 2 : Calculate moles of water ([tex]H_{2}O[/tex]) using moles of [tex]O_{2}[/tex] using mole ratio.
A mole ratio is the ratio between the amounts in moles of any two compounds involved in a chemical reaction. The mole ratio is determined by examining the coefficients in front of formulas in a balanced chemical equation.
The coefficient of [tex]H_{2}O[/tex] is 6 and coefficient of [tex]O_{2}[/tex] is 5, So mole ratio of [tex]H_{2}O[/tex] to [tex]O_{2}[/tex] is 6 : 5
Moles of [tex]H_{2}O[/tex] = [tex](0.060 mole O_{2})\times \frac{(6 mole H_{2}O)}{(5 mole O_{2})}[/tex]
[tex]Moles of H_{2}O = (0.060)\times \frac{(6 mole H_{2}O)}{(5)}[/tex]
[tex]Moles of H_{2}O = 0.072 mole H_{2}O[/tex]
0.072 moles of [tex]H_{2}O[/tex] is produced by the reaction of 0.060 mole oxygen ([tex]O_{2}[/tex])
The reaction between ammonia and oxygen will result in the formation of nitrogen gas and water molecule. In the given equation, 0.072 moles of water will be produced by the reaction of 0.060 mol of oxygen.
Given that,
Moles of oxygen = 0.060 mol
Moles of water = ?
The balanced chemical equation between ammonia and oxygen is :
- 4 NH₃ + 5 O₂ [tex]\rightarrow[/tex] 4 NO + 6 H₂O
From the stoichiometry of the equation, 5 moles of oxygen reacts with 4 moles of ammonia to yield 4 moles of nitrogen oxide and 6 moles of water.
The mole ratio is determined by examining the coefficients in front of formulas in a balanced chemical equation.
Calculating the moles of water as:
- Mole ratio of H₂O to O₂ is 6:5.
- Moles of H₂O = 0.060 moles of O₂ x [tex]\dfrac{\text{6 moles of H}_2\text O}{\text{5 moles of O}_2}[/tex]
- Moles of H₂O = 0.060 moles of O₂ x [tex]\dfrac{\text{6 moles of H}_2\text O}{\text{5}}[/tex]
- Moles of H₂O = 0.072 moles of H₂O.
Therefore, 0.072 moles of the H₂O will be produced by the reaction of 0.060 moles of oxygen.
To know more about mole ratio, refer to the following link:
https://brainly.com/question/15660071?referrer=searchResults
