contestada

If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitrobenzene = 123.06 g/mole) report answers to one decimal place

Respuesta :

Molality is defined as 1 mole of a solute in 1 kg of solvent.  

Molality=

[tex]\frac{Number of moles of solute}{Mass of solvent in kg}[/tex]

Number of moles of solute, n=  

[tex]\frac{Given mass of the substance}{Molar mass of the substance}[/tex]

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,  

[tex]n= \frac{0.2 }{123.06}[/tex]

Number of moles of nitrobenzene, n= 0.0016  mol

Mass of 10.9 g of naphthalene in kg=0.0109  

[tex]Molality= \frac{0.0016}{0.0109 }[/tex]

Molality= 0.146 m