Respuesta :

PBCHEM

Answer : 27 triangles

Explanation : Considering if one triangle has 1/18 [tex] m^{2} [/tex] area

n triangle have n x 1/18 [tex] m^{2} [/tex]

To composed an area of 3/2 [tex] m^{2} [/tex] we need to get 27 triangles each having an area of 1/18 [tex] m^{2} [/tex]

Since 27 ×1/18 [tex] m^{2} [/tex]

= 3/2 [tex] m^{2} [/tex]