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For a more difficult training session, the mass to be pushed is increased to 160 kg. If the players still push with a force of 150 N, what is the acceleration of the objection?
Use Newton's law:
F=ma
150 N=

Respuesta :

As you already written, you have to use Newton's law

[tex] F=ma[/tex]

where F is the force, m is the mass, and a is the acceleration.

You already know the mass and the force, so you have to solve the equality for the acceleration:

[tex] a = \dfrac{F}{m} [/tex]

plug the given values:

[tex] a = \dfrac{150}{160} = \dfrac{15}{16} = 0.9375 [/tex]

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