Respuesta :

konrad509

[tex] 2x-14\geq0\\\\
2x\geq14\\\\
x\geq7\\\\
D_f:x\in\langle7,\infty) [/tex]

sqdancefan

The square root function is only defined for non-negative arguments. So you must have

... 2x - 14 ≥ 0

... 2x ≥ 14

... x ≥ 7

In interval notation, x ∈ [7, ∞)

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