You need 4.0 ounces of a steroid ointment. if there are 16 oz in 1 lb, how many grams of ointment does the pharmacist need to prepare

Respuesta :

The given units are the units of masses which are interconvertable.

It is given that:

[tex] 1 lb = 16 oz [/tex]

Now, converting [tex] kg to lb [/tex]:

Since, [tex] 1 kg = 2.20462 lb  [/tex]

So, [tex] \frac{0.0625 lb}{1 oz}\times \frac{1 kg}{2.20462 lb} [/tex]

Now converting [tex] kg to g [/tex]:

Since, 1 kg = 1000 g

So, [tex] \frac{0.0625 lb}{1 oz}\times \frac{1 kg}{2.20462 lb}\times \frac{1000 g}{1 kg} = 28.349 \frac{g}{oz} [/tex]

For [tex] 4 oz [/tex]:

[tex] 28.349\frac{g}{oz} \times 4 oz = 113.396 g [/tex]

Thus, [tex] 113.396 g [/tex] of ointment needed to be prepared by the pharmacist.