We can calculate the time it takes for the object to hit the ground by using the following equation:
[tex] S=\frac{1}{2} gt^2 [/tex]
where S=10.5 m is the initial height of the object, [tex] g=9.81 m/s^2 [/tex] is the free-fall acceleration and t is the time. Re-arranging the equation, we can solve for the time:
[tex] t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(10.5 m)}{9.81 m/s^2}}=1.46 s [/tex]
