Let's assume
length of rectangle is L
width of rectangle is W
the width of a rectangle is 3 meters more than one-fourth its length
so,
[tex]W=3+\frac{1}{4} L[/tex]
the perimeter is 10 meters more than twice its length
we know that
perimeter =2(L+W)
so, we get
[tex]2(L+W)=10+2L[/tex]
now, we can simplify it
[tex]2L+2W=10+2L[/tex]
subtract both sides by 2L
[tex]2L+2W-2L=10+2L-2L[/tex]
[tex]2W=10[/tex]
[tex]W=5[/tex]
now, we can find L
[tex]5=3+\frac{1}{4} L[/tex]
subtract both sides 3
[tex]5-3=3-3+\frac{1}{4} L[/tex]
[tex]2=\frac{1}{4} L[/tex]
multiply both sides by 4
[tex]4*2=4*\frac{1}{4} L[/tex]
[tex]L=8[/tex]
so,
length of rectangle is 8 meter
width of rectangle is 5 meter ............Answer
