we are given
[tex] \frac{3x^2-4x+9}{x-2} [/tex]
we can see that
numerator is
[tex] 3x^2-4x+9 [/tex]
and denominator is
[tex] x-2 [/tex]
We always put coefficient of numerator inside box
we can see that coefficient of numerators are 3 , -4 and 9
and in the left side , we put value of x after putting denominator =0
[tex] x-2=0 [/tex]
[tex] x=2 [/tex]
so, left side will be 2
so, option-D..................Answer
