[tex] 3\sqrt{x+4}+3\sqrt{2x+8}=0 [/tex]
Subtract [tex] 3\sqrt{2x+8} [/tex] from both sides.
[tex] 3\sqrt{x+4}= -3\sqrt{2x+8} [/tex]
Square and expand both sides.
9x+36=18x+72
Subtract 9x from both sides.
36=9x+72
Subtract 72 from both sides.
-36=9x
Divide both sides by 9.
-4=x
Your answer would be -4.
I hope this helps :)
