If any of the parallel resistors is cut away, then the equivalent resistance seen by the battery INCREASES, while the current and power delivered by the battery both DECREASE.
Answer:
current will DECREASE in the circuit while equivalent resistance will INCREASE for the circuit
Explanation:
If three resistors are connected in parallel then in that case the equivalent resistance of all three is given by
[tex]\frac{1}{R_{eq}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R}[/tex]
so here we can say
[tex]R_{eq} = \frac{R}{3}[/tex]
now the current in the circuit is given as
[tex]i = \frac{V}{R_{eq}} = \frac{3V}{R}[/tex]
now if one of the resistance is removed from it
now the equivalent resistance is given as
[tex]\frac{1}{R_{eq}} = \frac{1}{R} + \frac{1}{R}[/tex]
so it is given as
[tex]R_{eq} = \frac{R}{2}[/tex]
now the current in the circuit is given as
[tex]i = \frac{V}{R_{eq}} = \frac{2V}{R}[/tex]
So current will DECREASE in the circuit while equivalent resistance will INCREASE for the circuit
