Respuesta :
[tex] \displaystyle
|\Omega|=\binom{52}{2}=\dfrac{52!}{2!50!}=\dfrac{51\cdot52}{2}=1326\\
|A|=\binom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{3\cdot4}{2}=6\\\\
P(A)=\dfrac{6}{1326}=\dfrac{1}{221} [/tex]
Hey,
It is given that total number of cards is 52 cards...
Total number of King cards=4
Number of favorable outcomes =2 King cards.....
P(getting 2king cards at random)=2/52=1/26 .....
Hope this helps u.....
It is given that total number of cards is 52 cards...
Total number of King cards=4
Number of favorable outcomes =2 King cards.....
P(getting 2king cards at random)=2/52=1/26 .....
Hope this helps u.....