need help with this math problem

If this factors nicely, you can cancel part of the numerator with the denominator. The whole denominator must go in this question. So let's see if 3y + 1 is a factor of the numerator.
Try factoring the numerator. One factor must be 3y + 1 if this is going to be able to be simplified.
(3y + 1)( y - 6) what should go before the y to get to 12? It should be 4
(3y + 1)(4y - 6) This does not give the correct middle term, so this is not reducable. Do you mean division? If you do, then the answer is 4y with a remainder of - 6/(3y + 1)