The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 78 inches, and a standard deviation of 16 inches. what is the probability that the mean annual precipitation during 64 randomly picked years will be less than 80.8 inches?

Respuesta :

The sample mean is μ=78, and sample standard deviation is σₓ=σ/[tex] \sqrt{n} [/tex]=16/[tex] \sqrt{64} [/tex]=2.

The Z-score is [tex] Z=\frac{80.8-78}{2} =1.4 [/tex].

The required probability

[tex] P(X<80.8)=P(Z<1.4) [/tex]

Refer to standard normal distribution table.

[tex] P(Z<1.4)=0.9192 [/tex]