please help !
Which function has the greatest rate of change on the interval from x = 0 to x = pi over 2?
f(x)
g(x)
h(x)
All three functions have the same rate of change.

please help Which function has the greatest rate of change on the interval from x 0 to x pi over 2 fx gx hx All three functions have the same rate of change class=

Respuesta :

The second option has the greatest rate of change

Answer:

The function that has the greatest rate of change is:

                     g(x)

Step-by-step explanation:

We know that the rate of change from x=a to x=b is determined as:

[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]

We are asked to find the rate of change of each of the functions form x=0 to x=pi over 2.

f(x):

We are given that:

[tex]f(\dfrac{\pi}{2})=2[/tex]

and,

[tex]f(0)=0[/tex]

Hence,

[tex]rate\ of\ change=\dfrac{2-0}{\dfrac{\pi}{2}-0}\\\\\\rate\ of\ change=\dfrac{4}{\pi}[/tex]

g(x):

We have:

[tex]g(0)=0[/tex]

and

[tex]g(\dfrac{\pi}{2})=4[/tex]

Hence,

[tex]rate\ of\ change=\dfrac{4-0}{\dfrac{\pi}{2}-0}\\\\\\rate\ of\ change=\dfrac{8}{\pi}[/tex]

h(x):

[tex]h(x)=\sin (x-\pi)+5[/tex]

Now we have:

[tex]h(0)=\sin (-\pi)+5\\\\h(0)=0+5\\\\h(0)=5[/tex]

Also,

[tex]h(\dfrac{\pi}{2})=\sin (\dfrac{\pi}{2}-\pi)+5\\\\\\h(\dfrac{\pi}{2})=\sin (\dfrac{-\pi}{2})+5\\\\h(\dfrac{\pi}{2})=-\sin (\dfrac{\pi}{2})+5\\\\\\h(\dfrac{\pi}{2})=-1+5\\\\h(\dfrac{\pi}{2})=4[/tex]

Hence, the rate of change is calculated as:

[tex]rate\ of\ change=\dfrac{4-5}{\dfrac{\pi}{2}-0}\\\\\\rate\ of\ change=\dfrac{-2}{\pi}[/tex]

               Hence, the greatest rate of change is:

                                g(x)

Since,

[tex]\dfrac{8}{\pi}>\dfrac{4}{\pi}>\dfrac{-2}{\pi}[/tex]