The relation between the legs and the hypotenuse of the right-angled triangle can be expressed using the Pythagorean theorem as follows:
[tex] hypotenuse = \sqrt{(leg1)^2 + (leg2)^2} [/tex]
We are given that a and b are the legs and we need to compute the hypotenuse. This means that all we need to do is substitute in the above formula.
Question 7:
a = 6 and b = 8
hypotenuse = [tex] \sqrt{(6)^2 + (8)^2} = 10 [/tex] units
Question 8:
a = 5 and b = 9
hypotenuse = [tex] \sqrt{(5)^2 + (9)^2} = 10.29 [/tex] units which is approximately 10.3 units
Question 9:
a = 4 and b = 10
hypotenuse = [tex] \sqrt{(4)^2 + (10)^2} = 10.77 [/tex] units which is approximately 10.8 units
Question 10:
a = 9 and b = 1
hypotenuse = [tex] \sqrt{(9)^2 + (1)^2} = 9.05 [/tex] units which is approximately 9.1 units
Question 11:
a = 7 and b = 3.5
hypotenuse = [tex] \sqrt{(7)^2 + (3.5)^2} = 7.82 [/tex] units which is approximately 7.8 units
Question 12:
a = 1.4 and b = 2.3
hypotenuse = [tex] \sqrt{(1.4)^2 + (2.3)^2} = 2.69 [/tex] units which is approximately 2.7 units
Hope this helps :)
