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Find the limit of the function algebraically.

limit as x approaches nine of quantity x squared minus eighty one divided by quantity x minus nine.

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Respuesta :

[tex]\bf \lim\limits_{x\to 9}~\cfrac{x^2-81}{x-9}\implies \cfrac{\stackrel{\textit{difference of squares}}{x^2-9^2}}{x-9}\implies \cfrac{\underline{(x-9)}(x+9)}{\underline{(x-9)}} \\\\\\ \lim\limits_{x\to 9}~x+9\implies (9)+9\implies 18[/tex]